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13149497 is a prime number
BaseRepresentation
bin110010001010…
…010100111001
3220202001201102
4302022110321
511331240442
61145501145
7216524504
oct62122471
926661642
1013149497
117471459
1244a17b5
13295528a
141a6413b
15124b232
hexc8a539

13149497 has 2 divisors, whose sum is σ = 13149498. Its totient is φ = 13149496.

The previous prime is 13149473. The next prime is 13149509. The reversal of 13149497 is 79494131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11417641 + 1731856 = 3379^2 + 1316^2 .

It is an emirp because it is prime and its reverse (79494131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13149497 is a prime.

It is a super-3 number, since 3×131494973 (a number of 22 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13149497.

It is not a weakly prime, because it can be changed into another prime (13149407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6574748 + 6574749.

It is an arithmetic number, because the mean of its divisors is an integer number (6574749).

Almost surely, 213149497 is an apocalyptic number.

It is an amenable number.

13149497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13149497 is an equidigital number, since it uses as much as digits as its factorization.

13149497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 27216, while the sum is 38.

The square root of 13149497 is about 3626.2235176558. The cubic root of 13149497 is about 236.0313625370.

The spelling of 13149497 in words is "thirteen million, one hundred forty-nine thousand, four hundred ninety-seven".