Base | Representation |
---|---|
bin | 1011111100111010111001… |
… | …0111000101000101110110 |
3 | 1201112021210221010021211012 |
4 | 2333032232113011011312 |
5 | 3210301214420303324 |
6 | 43540555310512222 |
7 | 2524264636022462 |
oct | 277165627050566 |
9 | 51467727107735 |
10 | 13141230244214 |
11 | 4207189977596 |
12 | 1582a37505672 |
13 | 74429c3a0a67 |
14 | 336078bb74a2 |
15 | 17bc783ba20e |
hex | bf3ae5c5176 |
13141230244214 has 4 divisors (see below), whose sum is σ = 19711845366324. Its totient is φ = 6570615122106.
The previous prime is 13141230244187. The next prime is 13141230244229. The reversal of 13141230244214 is 41244203214131.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×131412302442143 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285307561052 + ... + 3285307561055.
It is an arithmetic number, because the mean of its divisors is an integer number (4927961341581).
Almost surely, 213141230244214 is an apocalyptic number.
13141230244214 is a deficient number, since it is larger than the sum of its proper divisors (6570615122110).
13141230244214 is an equidigital number, since it uses as much as digits as its factorization.
13141230244214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6570615122109.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 13141230244214 its reverse (41244203214131), we get a palindrome (54385433458345).
The spelling of 13141230244214 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty million, two hundred forty-four thousand, two hundred fourteen".
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