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13141230244214 = 26570615122107
BaseRepresentation
bin1011111100111010111001…
…0111000101000101110110
31201112021210221010021211012
42333032232113011011312
53210301214420303324
643540555310512222
72524264636022462
oct277165627050566
951467727107735
1013141230244214
114207189977596
121582a37505672
1374429c3a0a67
14336078bb74a2
1517bc783ba20e
hexbf3ae5c5176

13141230244214 has 4 divisors (see below), whose sum is σ = 19711845366324. Its totient is φ = 6570615122106.

The previous prime is 13141230244187. The next prime is 13141230244229. The reversal of 13141230244214 is 41244203214131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×131412302442143 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285307561052 + ... + 3285307561055.

It is an arithmetic number, because the mean of its divisors is an integer number (4927961341581).

Almost surely, 213141230244214 is an apocalyptic number.

13141230244214 is a deficient number, since it is larger than the sum of its proper divisors (6570615122110).

13141230244214 is an equidigital number, since it uses as much as digits as its factorization.

13141230244214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6570615122109.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 13141230244214 its reverse (41244203214131), we get a palindrome (54385433458345).

The spelling of 13141230244214 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty million, two hundred forty-four thousand, two hundred fourteen".

Divisors: 1 2 6570615122107 13141230244214