Base | Representation |
---|---|
bin | 10011000111110010100… |
… | …101111101010101110011 |
3 | 11122121202100210111000010 |
4 | 103013302211331111303 |
5 | 133012120433442011 |
6 | 2443354231430003 |
7 | 163636004511021 |
oct | 23076245752563 |
9 | 4577670714003 |
10 | 1314035062131 |
11 | 4673085990a0 |
12 | 192803825303 |
13 | 96bb3a6142c |
14 | 4785758b711 |
15 | 242ab1821a6 |
hex | 131f297d573 |
1314035062131 has 16 divisors (see below), whose sum is σ = 1925913990528. Its totient is φ = 790305609600.
The previous prime is 1314035062127. The next prime is 1314035062157. The reversal of 1314035062131 is 1312605304131.
It is not a de Polignac number, because 1314035062131 - 22 = 1314035062127 is a prime.
It is a super-2 number, since 2×13140350621312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1314035062931) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151977526 + ... + 151986171.
It is an arithmetic number, because the mean of its divisors is an integer number (120369624408).
Almost surely, 21314035062131 is an apocalyptic number.
1314035062131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1314035062131 is a deficient number, since it is larger than the sum of its proper divisors (611878928397).
1314035062131 is a wasteful number, since it uses less digits than its factorization.
1314035062131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 303963842.
The product of its (nonzero) digits is 6480, while the sum is 30.
The spelling of 1314035062131 in words is "one trillion, three hundred fourteen billion, thirty-five million, sixty-two thousand, one hundred thirty-one".
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