Base | Representation |
---|---|
bin | 10011000111110010100… |
… | …100010111000111000111 |
3 | 11122121202100000012121112 |
4 | 103013302210113013013 |
5 | 133012120332042044 |
6 | 2443354214435235 |
7 | 163636001115152 |
oct | 23076244270707 |
9 | 4577670005545 |
10 | 1314034643399 |
11 | 467308332535 |
12 | 192803662b1b |
13 | 96bb394596a |
14 | 478574bcc99 |
15 | 242ab0ed09e |
hex | 131f29171c7 |
1314034643399 has 2 divisors, whose sum is σ = 1314034643400. Its totient is φ = 1314034643398.
The previous prime is 1314034643333. The next prime is 1314034643413. The reversal of 1314034643399 is 9933464304131.
It is a strong prime.
It is an emirp because it is prime and its reverse (9933464304131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314034643399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314034643309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657017321699 + 657017321700.
It is an arithmetic number, because the mean of its divisors is an integer number (657017321700).
Almost surely, 21314034643399 is an apocalyptic number.
1314034643399 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314034643399 is an equidigital number, since it uses as much as digits as its factorization.
1314034643399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2519424, while the sum is 50.
The spelling of 1314034643399 in words is "one trillion, three hundred fourteen billion, thirty-four million, six hundred forty-three thousand, three hundred ninety-nine".
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