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13140232501454 = 26570116250727
BaseRepresentation
bin1011111100110111001011…
…1000111111100011001110
31201112012020101200201001122
42333031302320333203032
53210242144010021304
643540312305440542
72524231132242452
oct277156270774316
951465211621048
1013140232501454
1142068177556a3
1215827b9340152
13744170774126
14335dc2496662
1517bc1a9d29be
hexbf372e3f8ce

13140232501454 has 4 divisors (see below), whose sum is σ = 19710348752184. Its totient is φ = 6570116250726.

The previous prime is 13140232501421. The next prime is 13140232501457. The reversal of 13140232501454 is 45410523204131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×131402325014543 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140232501457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285058125362 + ... + 3285058125365.

It is an arithmetic number, because the mean of its divisors is an integer number (4927587188046).

Almost surely, 213140232501454 is an apocalyptic number.

13140232501454 is a deficient number, since it is larger than the sum of its proper divisors (6570116250730).

13140232501454 is an equidigital number, since it uses as much as digits as its factorization.

13140232501454 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6570116250729.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 13140232501454 its reverse (45410523204131), we get a palindrome (58550755705585).

The spelling of 13140232501454 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-two million, five hundred one thousand, four hundred fifty-four".

Divisors: 1 2 6570116250727 13140232501454