131402230000001 has 4 divisors (see below), whose sum is σ = 131561892491712. Its totient is φ = 131242567508292.

The previous prime is 131402229999967. The next prime is 131402230000057. The reversal of 131402230000001 is 100000032204131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131402230000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131402230000081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79831244621 + ... + 79831246266.

It is an arithmetic number, because the mean of its divisors is an integer number (32890473122928).

Almost surely, 2^{131402230000001} is an apocalyptic number.

It is an amenable number.

131402230000001 is a deficient number, since it is larger than the sum of its proper divisors (159662491711).

131402230000001 is an equidigital number, since it uses as much as digits as its factorization.

131402230000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159662491710.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 131402230000001 its reverse (100000032204131), we get a palindrome (231402262204132).

The spelling of 131402230000001 in words is "one hundred thirty-one trillion, four hundred two billion, two hundred thirty million, one", and thus it is an aban number.