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13135316633 is a prime number
BaseRepresentation
bin11000011101110110…
…10000011010011001
31020220102102012222122
430032323100122121
5203400120113013
610011223231025
7643335230525
oct141673203231
936812365878
1013135316633
1156305a888a
122666ba8475
13131442c40a
148c8710d85
1551d280a08
hex30eed0699

13135316633 has 2 divisors, whose sum is σ = 13135316634. Its totient is φ = 13135316632.

The previous prime is 13135316573. The next prime is 13135316651. The reversal of 13135316633 is 33661353131.

13135316633 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12888606784 + 246709849 = 113528^2 + 15707^2 .

It is a cyclic number.

It is not a de Polignac number, because 13135316633 - 212 = 13135312537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13135316593 and 13135316602.

It is not a weakly prime, because it can be changed into another prime (13135316693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567658316 + 6567658317.

It is an arithmetic number, because the mean of its divisors is an integer number (6567658317).

Almost surely, 213135316633 is an apocalyptic number.

It is an amenable number.

13135316633 is a deficient number, since it is larger than the sum of its proper divisors (1).

13135316633 is an equidigital number, since it uses as much as digits as its factorization.

13135316633 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43740, while the sum is 35.

Adding to 13135316633 its reverse (33661353131), we get a palindrome (46796669764).

The spelling of 13135316633 in words is "thirteen billion, one hundred thirty-five million, three hundred sixteen thousand, six hundred thirty-three".