Base | Representation |
---|---|
bin | 10011000111000010000… |
… | …101101111011010011111 |
3 | 11122112122122120121002102 |
4 | 103013002011233122133 |
5 | 133003434123410421 |
6 | 2443141402115315 |
7 | 163606563650114 |
oct | 23070205573237 |
9 | 4575578517072 |
10 | 1313221310111 |
11 | 466a30215167 |
12 | 1926171abb3b |
13 | 96ab42a4c69 |
14 | 477bb48290b |
15 | 2425e9e060b |
hex | 131c216f69f |
1313221310111 has 4 divisors (see below), whose sum is σ = 1313224238424. Its totient is φ = 1313218381800.
The previous prime is 1313221309957. The next prime is 1313221310153. The reversal of 1313221310111 is 1110131223131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313221310111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313221310711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 634925 + ... + 1740566.
It is an arithmetic number, because the mean of its divisors is an integer number (328306059606).
Almost surely, 21313221310111 is an apocalyptic number.
1313221310111 is a deficient number, since it is larger than the sum of its proper divisors (2928313).
1313221310111 is an equidigital number, since it uses as much as digits as its factorization.
1313221310111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2928312.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1313221310111 its reverse (1110131223131), we get a palindrome (2423352533242).
The spelling of 1313221310111 in words is "one trillion, three hundred thirteen billion, two hundred twenty-one million, three hundred ten thousand, one hundred eleven".
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