Base | Representation |
---|---|
bin | 11000011101011101… |
… | …01001100100011011 |
3 | 1020220012012022121112 |
4 | 30032232221210123 |
5 | 203343243334203 |
6 | 10011024330535 |
7 | 643265154461 |
oct | 141656514433 |
9 | 36805168545 |
10 | 13132011803 |
11 | 5629750919 |
12 | 2665a73a4b |
13 | 13138430b1 |
14 | 8c80d0831 |
15 | 51cd2b6d8 |
hex | 30eba991b |
13132011803 has 2 divisors, whose sum is σ = 13132011804. Its totient is φ = 13132011802.
The previous prime is 13132011799. The next prime is 13132011817. The reversal of 13132011803 is 30811023131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13132011803 - 22 = 13132011799 is a prime.
It is not a weakly prime, because it can be changed into another prime (13132011833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566005901 + 6566005902.
It is an arithmetic number, because the mean of its divisors is an integer number (6566005902).
Almost surely, 213132011803 is an apocalyptic number.
13132011803 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132011803 is an equidigital number, since it uses as much as digits as its factorization.
13132011803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 13132011803 its reverse (30811023131), we get a palindrome (43943034934).
The spelling of 13132011803 in words is "thirteen billion, one hundred thirty-two million, eleven thousand, eight hundred three".
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