Base | Representation |
---|---|
bin | 11000011101011101… |
… | …01001100000011111 |
3 | 1020220012012022021012 |
4 | 30032232221200133 |
5 | 203343243332201 |
6 | 10011024325435 |
7 | 643265153651 |
oct | 141656514037 |
9 | 36805168235 |
10 | 13132011551 |
11 | 562975070a |
12 | 2665a7387b |
13 | 1313842c49 |
14 | 8c80d06d1 |
15 | 51cd2b5bb |
hex | 30eba981f |
13132011551 has 4 divisors (see below), whose sum is σ = 13132606392. Its totient is φ = 13131416712.
The previous prime is 13132011533. The next prime is 13132011569. The reversal of 13132011551 is 15511023131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13132011533) and next prime (13132011569).
It is a cyclic number.
It is not a de Polignac number, because 13132011551 - 214 = 13131995167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132011751) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262976 + ... + 308901.
It is an arithmetic number, because the mean of its divisors is an integer number (3283151598).
Almost surely, 213132011551 is an apocalyptic number.
13132011551 is a deficient number, since it is larger than the sum of its proper divisors (594841).
13132011551 is an equidigital number, since it uses as much as digits as its factorization.
13132011551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 594840.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 13132011551 its reverse (15511023131), we get a palindrome (28643034682).
The spelling of 13132011551 in words is "thirteen billion, one hundred thirty-two million, eleven thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •