Base | Representation |
---|---|
bin | 1011111100010001011110… |
… | …1010011010111000011001 |
3 | 1201111020010002012222102221 |
4 | 2333010113222122320121 |
5 | 3210110432134114433 |
6 | 43531520140424041 |
7 | 2523422262462553 |
oct | 277042752327031 |
9 | 51436102188387 |
10 | 13130112019993 |
11 | 42024a3a30131 |
12 | 1580853b48021 |
13 | 743219b21867 |
14 | 3357023304d3 |
15 | 17b82727672d |
hex | bf117a9ae19 |
13130112019993 has 2 divisors, whose sum is σ = 13130112019994. Its totient is φ = 13130112019992.
The previous prime is 13130112019949. The next prime is 13130112020041. The reversal of 13130112019993 is 39991021103131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12810901709824 + 319210310169 = 3579232^2 + 564987^2 .
It is a cyclic number.
It is not a de Polignac number, because 13130112019993 - 29 = 13130112019481 is a prime.
It is not a weakly prime, because it can be changed into another prime (13130112719993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565056009996 + 6565056009997.
It is an arithmetic number, because the mean of its divisors is an integer number (6565056009997).
Almost surely, 213130112019993 is an apocalyptic number.
It is an amenable number.
13130112019993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130112019993 is an equidigital number, since it uses as much as digits as its factorization.
13130112019993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39366, while the sum is 43.
The spelling of 13130112019993 in words is "thirteen trillion, one hundred thirty billion, one hundred twelve million, nineteen thousand, nine hundred ninety-three".
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