Base | Representation |
---|---|
bin | 11101110101001111100001… |
… | …101110011101010110001100 |
3 | 122012112210200122001022222012 |
4 | 131311033201232131112030 |
5 | 114144104002134341330 |
6 | 1143013234221440352 |
7 | 36431020443033011 |
oct | 3565174156352614 |
9 | 565483618038865 |
10 | 131202153043340 |
11 | 3889457aa61685 |
12 | 1286ba337100b8 |
13 | 5829404c40422 |
14 | 245830a61d708 |
15 | 1027d082c7c95 |
hex | 7753e1b9d58c |
131202153043340 has 24 divisors (see below), whose sum is σ = 276263193045840. Its totient is φ = 52340161854528.
The previous prime is 131202153043331. The next prime is 131202153043517. The reversal of 131202153043340 is 43340351202131.
It is a junction number, because it is equal to n+sod(n) for n = 131202153043297 and 131202153043306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8793702530 + ... + 8793717449.
It is an arithmetic number, because the mean of its divisors is an integer number (11510966376910).
Almost surely, 2131202153043340 is an apocalyptic number.
131202153043340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131202153043340 is an abundant number, since it is smaller than the sum of its proper divisors (145061040002500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131202153043340 is a wasteful number, since it uses less digits than its factorization.
131202153043340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17587420361 (or 17587420359 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
The spelling of 131202153043340 in words is "one hundred thirty-one trillion, two hundred two billion, one hundred fifty-three million, forty-three thousand, three hundred forty".
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