Base | Representation |
---|---|
bin | 1011111011101100000000… |
… | …0100011011110100111010 |
3 | 1201110021011000110220222010 |
4 | 2332323000010123310322 |
5 | 3204424331420310020 |
6 | 43523134030310350 |
7 | 2522615063164245 |
oct | 276730004336472 |
9 | 51407130426863 |
10 | 13120052510010 |
11 | 41a920166a416 |
12 | 157a9070583b6 |
13 | 7422a59c94a4 |
14 | 33502a31a25c |
15 | 17b439060de0 |
hex | beec011bd3a |
13120052510010 has 16 divisors (see below), whose sum is σ = 31488126024096. Its totient is φ = 3498680669328.
The previous prime is 13120052510009. The next prime is 13120052510021. The reversal of 13120052510010 is 1001525002131.
It is a super-3 number, since 3×131200525100103 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218667541804 + ... + 218667541863.
It is an arithmetic number, because the mean of its divisors is an integer number (1968007876506).
Almost surely, 213120052510010 is an apocalyptic number.
13120052510010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13120052510010 is an abundant number, since it is smaller than the sum of its proper divisors (18368073514086).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120052510010 is a wasteful number, since it uses less digits than its factorization.
13120052510010 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 437335083677.
The product of its (nonzero) digits is 300, while the sum is 21.
Adding to 13120052510010 its reverse (1001525002131), we get a palindrome (14121577512141).
The spelling of 13120052510010 in words is "thirteen trillion, one hundred twenty billion, fifty-two million, five hundred ten thousand, ten".
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