131144330000 has 50 divisors (see below), whose sum is σ = 317513561574. Its totient is φ = 52457728000.

The previous prime is 131144329991. The next prime is 131144330011. The reversal of 131144330000 is 33441131.

It can be written as a sum of positive squares in 5 ways, for example, as 99409045264 + 31735284736 = 315292^2 + 178144^2 .

It is a tau number, because it is divible by the number of its divisors (50).

It is a super-2 number, since 2×131144330000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6547217 + ... + 6567216.

Almost surely, 2^131144330000 is an apocalyptic number.

131144330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131144330000 is an abundant number, since it is smaller than the sum of its proper divisors (186369231574).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131144330000 is an equidigital number, since it uses as much as digits as its factorization.

131144330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13114461 (or 13114440 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131144330000 its reverse (33441131), we get a palindrome (131177771131).

The spelling of 131144330000 in words is "one hundred thirty-one billion, one hundred forty-four million, three hundred thirty thousand".