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13114340133402 = 238925792448773
BaseRepresentation
bin1011111011010110101110…
…0101011100101000011010
31201102201101220122010102010
42332311223211130220122
53204331132033232102
643520351130250350
72522323400610114
oct276655345345032
951381356563363
1013114340133402
1141a684012a312
121579791b869b6
137418a53b6ca1
14334a477bc3b4
1517b2027ded6c
hexbed6b95ca1a

13114340133402 has 16 divisors (see below), whose sum is σ = 26228720363040. Its totient is φ = 4371440028432.

The previous prime is 13114340133383. The next prime is 13114340133407. The reversal of 13114340133402 is 20433104341131.

It is a self number, because there is not a number n which added to its sum of digits gives 13114340133402.

It is not an unprimeable number, because it can be changed into a prime (13114340133407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4131088 + ... + 6579860.

It is an arithmetic number, because the mean of its divisors is an integer number (1639295022690).

Almost surely, 213114340133402 is an apocalyptic number.

13114340133402 is an abundant number, since it is smaller than the sum of its proper divisors (13114380229638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114340133402 is a wasteful number, since it uses less digits than its factorization.

13114340133402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3341357.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 13114340133402 its reverse (20433104341131), we get a palindrome (33547444474533).

The spelling of 13114340133402 in words is "thirteen trillion, one hundred fourteen billion, three hundred forty million, one hundred thirty-three thousand, four hundred two".

Divisors: 1 2 3 6 892579 1785158 2448773 2677737 4897546 5355474 7346319 14692638 2185723355567 4371446711134 6557170066701 13114340133402