Base | Representation |
---|---|
bin | 11101110100010110111100… |
… | …101100011110001101010000 |
3 | 122012022222212210122220221112 |
4 | 131310112330230132031100 |
5 | 114142110042432122230 |
6 | 1142525310052512452 |
7 | 36423440125423010 |
oct | 3564267454361520 |
9 | 565288783586845 |
10 | 131141402223440 |
11 | 38870835784504 |
12 | 128600ba31b728 |
13 | 5823772a8c50b |
14 | 24553c6163c40 |
15 | 102644ebb4d95 |
hex | 7745bcb1e350 |
131141402223440 has 160 divisors (see below), whose sum is σ = 350872084225536. Its totient is φ = 44651890483200.
The previous prime is 131141402223439. The next prime is 131141402223449. The reversal of 131141402223440 is 44322204141131.
It is a junction number, because it is equal to n+sod(n) for n = 131141402223397 and 131141402223406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131141402223449) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 290068604 + ... + 290520356.
Almost surely, 2131141402223440 is an apocalyptic number.
131141402223440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131141402223440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (175436042112768).
131141402223440 is an abundant number, since it is smaller than the sum of its proper divisors (219730682002096).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141402223440 is a wasteful number, since it uses less digits than its factorization.
131141402223440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 455357 (or 455351 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 131141402223440 its reverse (44322204141131), we get a palindrome (175463606364571).
The spelling of 131141402223440 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred two million, two hundred twenty-three thousand, four hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •