Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …001011101111110001101100 |
3 | 122012022222201200210222000112 |
4 | 131310112321023233301230 |
5 | 114142104432342004004 |
6 | 1142525300150115152 |
7 | 36423435511614323 |
oct | 3564267113576154 |
9 | 565288650728015 |
10 | 131141343313004 |
11 | 388708054a81a2 |
12 | 128600a264bab8 |
13 | 582376380447b |
14 | 24553bc3cb0ba |
15 | 1026449929e6e |
hex | 7745b92efc6c |
131141343313004 has 12 divisors (see below), whose sum is σ = 239475496484784. Its totient is φ = 62719772888784.
The previous prime is 131141343312989. The next prime is 131141343313031. The reversal of 131141343313004 is 400313343141131.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 712724691827 + ... + 712724692010.
It is an arithmetic number, because the mean of its divisors is an integer number (19956291373732).
Almost surely, 2131141343313004 is an apocalyptic number.
It is an amenable number.
131141343313004 is a deficient number, since it is larger than the sum of its proper divisors (108334153171780).
131141343313004 is a wasteful number, since it uses less digits than its factorization.
131141343313004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1425449383864 (or 1425449383862 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 131141343313004 its reverse (400313343141131), we get a palindrome (531454686454135).
The spelling of 131141343313004 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-three million, three hundred thirteen thousand, four".
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