1311320231131 has 4 divisors (see below), whose sum is σ = 1311333625512. Its totient is φ = 1311306836752.

The previous prime is 1311320231129. The next prime is 1311320231161.

1311320231131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311320231131 - 2¹ = 1311320231129 is a prime.

It is a super-2 number, since 2×1311320231131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311320231161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6549250 + ... + 6746503.

It is an arithmetic number, because the mean of its divisors is an integer number (327833406378).

Almost surely, 2^{1311320231131} is an apocalyptic number.

1311320231131 is a deficient number, since it is larger than the sum of its proper divisors (13394381).

1311320231131 is an equidigital number, since it uses as much as digits as its factorization.

1311320231131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13394380.

The product of its (nonzero) digits is 324, while the sum is 22.

It can be divided in two parts, 1311320 and 231131, that added together give a palindrome (1542451).

The spelling of 1311320231131 in words is "one trillion, three hundred eleven billion, three hundred twenty million, two hundred thirty-one thousand, one hundred thirty-one".