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13113113231354 = 26556556615677
BaseRepresentation
bin1011111011010010001001…
…1101001011111111111010
31201102121020102000001012112
42332310202131023333322
53204321123441400404
643520025301412322
72522251112245163
oct276644235137772
951377212001175
1013113113231354
1141a6270619684
1215794ab10a0a2
1374173b163946
1433496c88876a
1517b17ec3d56e
hexbed2274bffa

13113113231354 has 4 divisors (see below), whose sum is σ = 19669669847034. Its totient is φ = 6556556615676.

The previous prime is 13113113231341. The next prime is 13113113231411. The reversal of 13113113231354 is 45313231131131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6787249405225 + 6325863826129 = 2605235^2 + 2515127^2 .

It is a super-2 number, since 2×131131132313542 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13113113231354.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278278307837 + ... + 3278278307840.

Almost surely, 213113113231354 is an apocalyptic number.

13113113231354 is a deficient number, since it is larger than the sum of its proper divisors (6556556615680).

13113113231354 is an equidigital number, since it uses as much as digits as its factorization.

13113113231354 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6556556615679.

The product of its digits is 9720, while the sum is 32.

Adding to 13113113231354 its reverse (45313231131131), we get a palindrome (58426344362485).

The spelling of 13113113231354 in words is "thirteen trillion, one hundred thirteen billion, one hundred thirteen million, two hundred thirty-one thousand, three hundred fifty-four".

Divisors: 1 2 6556556615677 13113113231354