Base | Representation |
---|---|
bin | 1011111011010010001001… |
… | …1101001011111111111010 |
3 | 1201102121020102000001012112 |
4 | 2332310202131023333322 |
5 | 3204321123441400404 |
6 | 43520025301412322 |
7 | 2522251112245163 |
oct | 276644235137772 |
9 | 51377212001175 |
10 | 13113113231354 |
11 | 41a6270619684 |
12 | 15794ab10a0a2 |
13 | 74173b163946 |
14 | 33496c88876a |
15 | 17b17ec3d56e |
hex | bed2274bffa |
13113113231354 has 4 divisors (see below), whose sum is σ = 19669669847034. Its totient is φ = 6556556615676.
The previous prime is 13113113231341. The next prime is 13113113231411. The reversal of 13113113231354 is 45313231131131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6787249405225 + 6325863826129 = 2605235^2 + 2515127^2 .
It is a super-2 number, since 2×131131132313542 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13113113231354.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278278307837 + ... + 3278278307840.
Almost surely, 213113113231354 is an apocalyptic number.
13113113231354 is a deficient number, since it is larger than the sum of its proper divisors (6556556615680).
13113113231354 is an equidigital number, since it uses as much as digits as its factorization.
13113113231354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6556556615679.
The product of its digits is 9720, while the sum is 32.
Adding to 13113113231354 its reverse (45313231131131), we get a palindrome (58426344362485).
The spelling of 13113113231354 in words is "thirteen trillion, one hundred thirteen billion, one hundred thirteen million, two hundred thirty-one thousand, three hundred fifty-four".
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