Base | Representation |
---|---|
bin | 11101110100000101000110… |
… | …001000110101100000100110 |
3 | 122012021011101212221202211021 |
4 | 131310011012020311200212 |
5 | 114141301313211113110 |
6 | 1142512420012201354 |
7 | 36422161114316566 |
oct | 3564050610654046 |
9 | 565234355852737 |
10 | 131122233301030 |
11 | 38863699392374 |
12 | 1285844a76925a |
13 | 5821a0962908a |
14 | 24544c83b6da6 |
15 | 1025bcbdae2da |
hex | 774146235826 |
131122233301030 has 16 divisors (see below), whose sum is σ = 236023948080144. Its totient is φ = 52448020400800.
The previous prime is 131122233301001. The next prime is 131122233301039. The reversal of 131122233301030 is 30103332221131.
It is a junction number, because it is equal to n+sod(n) for n = 131122233300986 and 131122233301004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131122233301039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108483892 + ... + 109685911.
It is an arithmetic number, because the mean of its divisors is an integer number (14751496755009).
Almost surely, 2131122233301030 is an apocalyptic number.
131122233301030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131122233301030 is a deficient number, since it is larger than the sum of its proper divisors (104901714779114).
131122233301030 is a wasteful number, since it uses less digits than its factorization.
131122233301030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218229911.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 131122233301030 its reverse (30103332221131), we get a palindrome (161225565522161).
The spelling of 131122233301030 in words is "one hundred thirty-one trillion, one hundred twenty-two billion, two hundred thirty-three million, three hundred one thousand, thirty".
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