13112023021233 has 4 divisors (see below), whose sum is σ = 17482697361648. Its totient is φ = 8741348680820.

The previous prime is 13112023021231. The next prime is 13112023021241. The reversal of 13112023021233 is 33212032021131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13112023021233 - 2¹ = 13112023021231 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13112023021231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185337170203 + ... + 2185337170208.

It is an arithmetic number, because the mean of its divisors is an integer number (4370674340412).

Almost surely, 2^{13112023021233} is an apocalyptic number.

It is an amenable number.

13112023021233 is a deficient number, since it is larger than the sum of its proper divisors (4370674340415).

13112023021233 is an equidigital number, since it uses as much as digits as its factorization.

13112023021233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4370674340414.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 13112023021233 its reverse (33212032021131), we get a palindrome (46324055042364).

The spelling of 13112023021233 in words is "thirteen trillion, one hundred twelve billion, twenty-three million, twenty-one thousand, two hundred thirty-three".