13111444051 has 4 divisors (see below), whose sum is σ = 13116962392. Its totient is φ = 13105925712.

The previous prime is 13111444043. The next prime is 13111444063. The reversal of 13111444051 is 15044411131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15044411131 = 4091 ⋅3677441.

It is a cyclic number.

It is not a de Polignac number, because 13111444051 - 2³ = 13111444043 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111444091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2755605 + ... + 2760358.

It is an arithmetic number, because the mean of its divisors is an integer number (3279240598).

Almost surely, 2^13111444051 is an apocalyptic number.

13111444051 is a deficient number, since it is larger than the sum of its proper divisors (5518341).

13111444051 is an equidigital number, since it uses as much as digits as its factorization.

13111444051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5518340.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 13111444051 its reverse (15044411131), we get a palindrome (28155855182).

The spelling of 13111444051 in words is "thirteen billion, one hundred eleven million, four hundred forty-four thousand, fifty-one".