13104333131 has 4 divisors (see below), whose sum is σ = 13104596064. Its totient is φ = 13104070200.

The previous prime is 13104333083. The next prime is 13104333139. The reversal of 13104333131 is 13133340131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13133340131 = 109 ⋅120489359.

It is a cyclic number.

It is not a de Polignac number, because 13104333131 - 2¹⁰ = 13104332107 is a prime.

It is a super-2 number, since 2×13104333131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104333097 and 13104333106.

It is not an unprimeable number, because it can be changed into a prime (13104333139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31235 + ... + 164876.

It is an arithmetic number, because the mean of its divisors is an integer number (3276149016).

Almost surely, 2^13104333131 is an apocalyptic number.

13104333131 is a deficient number, since it is larger than the sum of its proper divisors (262933).

13104333131 is an equidigital number, since it uses as much as digits as its factorization.

13104333131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262932.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13104333131 its reverse (13133340131), we get a palindrome (26237673262).

The spelling of 13104333131 in words is "thirteen billion, one hundred four million, three hundred thirty-three thousand, one hundred thirty-one".