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13104030012973 is a prime number
BaseRepresentation
bin1011111010110000010100…
…0011011101011000101101
31201101201210101022202000221
42332230011003131120231
53204144023140403343
643511524104451341
72521510036205014
oct276540503353055
951351711282027
1013104030012973
1141a242a359229
121577795179b51
13740921397403
1433434a3ada7b
1517acec5c45ed
hexbeb050dd62d

13104030012973 has 2 divisors, whose sum is σ = 13104030012974. Its totient is φ = 13104030012972.

The previous prime is 13104030012971. The next prime is 13104030013001. The reversal of 13104030012973 is 37921003040131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10670139844324 + 2433890168649 = 3266518^2 + 1560093^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104030012973 - 21 = 13104030012971 is a prime.

Together with 13104030012971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104030012971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552015006486 + 6552015006487.

It is an arithmetic number, because the mean of its divisors is an integer number (6552015006487).

Almost surely, 213104030012973 is an apocalyptic number.

It is an amenable number.

13104030012973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104030012973 is an equidigital number, since it uses as much as digits as its factorization.

13104030012973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 34.

The spelling of 13104030012973 in words is "thirteen trillion, one hundred four billion, thirty million, twelve thousand, nine hundred seventy-three".