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131021110313 = 533163781567
BaseRepresentation
bin111101000000101110…
…1110111110000101001
3110112012002100000122022
41322001131313300221
54121312401012223
6140105033034225
712315553030232
oct1720135676051
9415162300568
10131021110313
1150625001455
1221486855975
13c4805c3612
1464acd50089
15361c814ac8
hex1e81777c29

131021110313 has 8 divisors (see below), whose sum is σ = 133535582208. Its totient is φ = 128508207984.

The previous prime is 131021110303. The next prime is 131021110331. The reversal of 131021110313 is 313011120131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131021110313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131021110291 and 131021110300.

It is not an unprimeable number, because it can be changed into a prime (131021110303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 223145 + ... + 558422.

It is an arithmetic number, because the mean of its divisors is an integer number (16691947776).

Almost surely, 2131021110313 is an apocalyptic number.

It is an amenable number.

131021110313 is a deficient number, since it is larger than the sum of its proper divisors (2514471895).

131021110313 is an equidigital number, since it uses as much as digits as its factorization.

131021110313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 784783.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131021110313 its reverse (313011120131), we get a palindrome (444032230444).

The spelling of 131021110313 in words is "one hundred thirty-one billion, twenty-one million, one hundred ten thousand, three hundred thirteen".

Divisors: 1 53 3163 167639 781567 41423051 2472096421 131021110313