131014443433 has 4 divisors (see below), whose sum is σ = 133235027280. Its totient is φ = 128793859588.

The previous prime is 131014443431. The next prime is 131014443491. The reversal of 131014443433 is 334344410131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131014443433 - 2¹ = 131014443431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131014443395 and 131014443404.

It is not an unprimeable number, because it can be changed into a prime (131014443431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1110291835 + ... + 1110291952.

It is an arithmetic number, because the mean of its divisors is an integer number (33308756820).

Almost surely, 2^131014443433 is an apocalyptic number.

It is an amenable number.

131014443433 is a deficient number, since it is larger than the sum of its proper divisors (2220583847).

131014443433 is an equidigital number, since it uses as much as digits as its factorization.

131014443433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2220583846.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 131014443433 its reverse (334344410131), we get a palindrome (465358853564).

The spelling of 131014443433 in words is "one hundred thirty-one billion, fourteen million, four hundred forty-three thousand, four hundred thirty-three".