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131014252002503 = 473049914246401
BaseRepresentation
bin11101110010100000100001…
…111100110111110011000111
3122011212211200111002110021102
4131302200201330313303013
5114133014142003040003
61142351041054210315
736411316204401302
oct3562404174676307
9564784614073242
10131014252002503
11388219177a2591
121283b533ab399b
13581478b4238ac
14244d1a3359b39
151022eac120588
hex772821f37cc7

131014252002503 has 8 divisors (see below), whose sum is σ = 133845673252800. Its totient is φ = 128184659251200.

The previous prime is 131014252002421. The next prime is 131014252002509. The reversal of 131014252002503 is 305200252410131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131014252002503 - 236 = 130945532525767 is a prime.

It is a super-2 number, since 2×1310142520025032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131014252002509) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 456979898 + ... + 457266503.

It is an arithmetic number, because the mean of its divisors is an integer number (16730709156600).

Almost surely, 2131014252002503 is an apocalyptic number.

131014252002503 is a deficient number, since it is larger than the sum of its proper divisors (2831421250297).

131014252002503 is an equidigital number, since it uses as much as digits as its factorization.

131014252002503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 914249497.

The product of its (nonzero) digits is 7200, while the sum is 29.

The spelling of 131014252002503 in words is "one hundred thirty-one trillion, fourteen billion, two hundred fifty-two million, two thousand, five hundred three".

Divisors: 1 47 3049 143303 914246401 42969580847 2787537276649 131014252002503