Base | Representation |
---|---|
bin | 1011111010100011010110… |
… | …1010100100101000010111 |
3 | 1201101101210220012112001101 |
4 | 2332220311222210220113 |
5 | 3204114411423332320 |
6 | 43510150533010531 |
7 | 2521324566552304 |
oct | 276506552445027 |
9 | 51341726175041 |
10 | 13100550605335 |
11 | 41a0a04316826 |
12 | 1576b83a83a47 |
13 | 7404b858aa1b |
14 | 3340da2520ab |
15 | 17ab96dd3c0a |
hex | bea35aa4a17 |
13100550605335 has 16 divisors (see below), whose sum is σ = 15959432996352. Its totient is φ = 10322345536000.
The previous prime is 13100550605287. The next prime is 13100550605339. The reversal of 13100550605335 is 53350605500131.
It is not a de Polignac number, because 13100550605335 - 213 = 13100550597143 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13100550605294 and 13100550605303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100550605339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67813714 + ... + 68006623.
It is an arithmetic number, because the mean of its divisors is an integer number (997464562272).
Almost surely, 213100550605335 is an apocalyptic number.
13100550605335 is a deficient number, since it is larger than the sum of its proper divisors (2858882391017).
13100550605335 is a wasteful number, since it uses less digits than its factorization.
13100550605335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 135820634.
The product of its (nonzero) digits is 101250, while the sum is 37.
The spelling of 13100550605335 in words is "thirteen trillion, one hundred billion, five hundred fifty million, six hundred five thousand, three hundred thirty-five".
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