1310010103 has 4 divisors (see below), whose sum is σ = 1366967088. Its totient is φ = 1253053120.

The previous prime is 1310010077. The next prime is 1310010131. The reversal of 1310010103 is 3010100131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3010100131 = 227 ⋅13260353.

It is a cyclic number.

It is not a de Polignac number, because 1310010103 - 2⁵ = 1310010071 is a prime.

It is a super-2 number, since 2×1310010103² = 3432252939924141218, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1310010103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310010133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28478458 + ... + 28478503.

It is an arithmetic number, because the mean of its divisors is an integer number (341741772).

Almost surely, 2^1310010103 is an apocalyptic number.

1310010103 is a deficient number, since it is larger than the sum of its proper divisors (56956985).

1310010103 is an equidigital number, since it uses as much as digits as its factorization.

1310010103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56956984.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 1310010103 is about 36194.0617090705. The cubic root of 1310010103 is about 1094.1869942171.

Adding to 1310010103 its reverse (3010100131), we get a palindrome (4320110234).

The spelling of 1310010103 in words is "one billion, three hundred ten million, ten thousand, one hundred three".