Base | Representation |
---|---|
bin | 1011111000011111011111… |
… | …1011111001011001101111 |
3 | 1201021000110010112200220122 |
4 | 2332013313323321121233 |
5 | 3203024414214033403 |
6 | 43442014403035155 |
7 | 2515632504010256 |
oct | 276076773713157 |
9 | 51230403480818 |
10 | 13065155221103 |
11 | 41879a0572767 |
12 | 157014606babb |
13 | 73a06748069b |
14 | 3324dd42379d |
15 | 179cc47a2838 |
hex | be1f7ef966f |
13065155221103 has 4 divisors (see below), whose sum is σ = 13148372770440. Its totient is φ = 12981937671768.
The previous prime is 13065155221093. The next prime is 13065155221127. The reversal of 13065155221103 is 30112255156031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13065155221103 - 218 = 13065154958959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13065155121103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41608774433 + ... + 41608774746.
It is an arithmetic number, because the mean of its divisors is an integer number (3287093192610).
Almost surely, 213065155221103 is an apocalyptic number.
13065155221103 is a deficient number, since it is larger than the sum of its proper divisors (83217549337).
13065155221103 is an equidigital number, since it uses as much as digits as its factorization.
13065155221103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83217549336.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 13065155221103 in words is "thirteen trillion, sixty-five billion, one hundred fifty-five million, two hundred twenty-one thousand, one hundred three".
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