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13055114151 = 323739204547
BaseRepresentation
bin11000010100010010…
…10011101110100111
31020200211111111212100
430022021103232213
5203214102123101
65555240223143
7641342432202
oct141211235647
936624444770
1013055114151
11559a2a9542
12264416aab3
13130092ab21
148bbbd4939
155161dbe86
hex30a253ba7

13055114151 has 12 divisors (see below), whose sum is σ = 19367046712. Its totient is φ = 8468181936.

The previous prime is 13055114131. The next prime is 13055114159. The reversal of 13055114151 is 15141155031.

13055114151 is a `hidden beast` number, since 130 + 5 + 511 + 4 + 15 + 1 = 666.

13055114151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13055114151 - 25 = 13055114119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13055114159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19601941 + ... + 19602606.

Almost surely, 213055114151 is an apocalyptic number.

13055114151 is a deficient number, since it is larger than the sum of its proper divisors (6311932561).

13055114151 is a wasteful number, since it uses less digits than its factorization.

13055114151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39204590 (or 39204587 counting only the distinct ones).

The product of its (nonzero) digits is 1500, while the sum is 27.

Adding to 13055114151 its reverse (15141155031), we get a palindrome (28196269182).

The spelling of 13055114151 in words is "thirteen billion, fifty-five million, one hundred fourteen thousand, one hundred fifty-one".

Divisors: 1 3 9 37 111 333 39204547 117613641 352840923 1450568239 4351704717 13055114151