13023113333 has 2 divisors, whose sum is σ = 13023113334. Its totient is φ = 13023113332.

The previous prime is 13023113287. The next prime is 13023113471. The reversal of 13023113333 is 33331132031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6652359844 + 6370753489 = 81562^2 + 79817^2 .

It is a cyclic number.

It is not a de Polignac number, because 13023113333 - 2¹² = 13023109237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13023113299 and 13023113308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13023113633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511556666 + 6511556667.

It is an arithmetic number, because the mean of its divisors is an integer number (6511556667).

Almost surely, 2^13023113333 is an apocalyptic number.

It is an amenable number.

13023113333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023113333 is an equidigital number, since it uses as much as digits as its factorization.

13023113333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 13023113333 its reverse (33331132031), we get a palindrome (46354245364).

The spelling of 13023113333 in words is "thirteen billion, twenty-three million, one hundred thirteen thousand, three hundred thirty-three".