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13015683357 = 34338561119
BaseRepresentation
bin11000001111100101…
…11001000100011101
31020121002022012222120
430013302321010131
5203124003331412
65551311133153
7640353324465
oct140762710435
936532265876
1013015683357
11557a017606
122632b141b9
1312c57033b1
148b688cba5
155129edb8c
hex307cb911d

13015683357 has 4 divisors (see below), whose sum is σ = 17354244480. Its totient is φ = 8677122236.

The previous prime is 13015683353. The next prime is 13015683379. The reversal of 13015683357 is 75338651031.

13015683357 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13015683357 - 22 = 13015683353 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13015683353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2169280557 + ... + 2169280562.

It is an arithmetic number, because the mean of its divisors is an integer number (4338561120).

Almost surely, 213015683357 is an apocalyptic number.

It is an amenable number.

13015683357 is a deficient number, since it is larger than the sum of its proper divisors (4338561123).

13015683357 is an equidigital number, since it uses as much as digits as its factorization.

13015683357 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4338561122.

The product of its (nonzero) digits is 226800, while the sum is 42.

The spelling of 13015683357 in words is "thirteen billion, fifteen million, six hundred eighty-three thousand, three hundred fifty-seven".

Divisors: 1 3 4338561119 13015683357