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130111032000 = 2635316133361
BaseRepresentation
bin111100100101100111…
…0001100101011000000
3110102211122212020220010
41321023032030223000
54112431411011000
6135434442544520
712254162344545
oct1711316145300
9412748766803
10130111032000
11501a8316114
1221271b08140
13c366bab841
14642412cbcc
1535b7996d50
hex1e4b38cac0

130111032000 has 224 divisors, whose sum is σ = 430020886464. Its totient is φ = 34664448000.

The previous prime is 130111031987. The next prime is 130111032053. The reversal of 130111032000 is 230111031.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 38710320 + ... + 38713680.

Almost surely, 2130111032000 is an apocalyptic number.

130111032000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130111032000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215010443232).

130111032000 is an abundant number, since it is smaller than the sum of its proper divisors (299909854464).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130111032000 is a wasteful number, since it uses less digits than its factorization.

130111032000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5004 (or 4984 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 130111032000 its reverse (230111031), we get a palindrome (130341143031).

The spelling of 130111032000 in words is "one hundred thirty billion, one hundred eleven million, thirty-two thousand".