Base | Representation |
---|---|
bin | 11101100101001111000010… |
… | …110001100000011001110111 |
3 | 122001122122022120210112112001 |
4 | 131211033002301200121313 |
5 | 114023043121230331243 |
6 | 1140412031221240131 |
7 | 36255365604335236 |
oct | 3545170261403167 |
9 | 561578276715461 |
10 | 130102122120823 |
11 | 38500000200096 |
12 | 127127b5563047 |
13 | 5779767929308 |
14 | 241ad94dc6b1d |
15 | 10093c4c69a4d |
hex | 7653c2c60677 |
130102122120823 has 2 divisors, whose sum is σ = 130102122120824. Its totient is φ = 130102122120822.
The previous prime is 130102122120811. The next prime is 130102122120827. The reversal of 130102122120823 is 328021221201031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130102122120823 - 241 = 127903098865271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130102122120791 and 130102122120800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130102122120827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051061060411 + 65051061060412.
It is an arithmetic number, because the mean of its divisors is an integer number (65051061060412).
Almost surely, 2130102122120823 is an apocalyptic number.
130102122120823 is a deficient number, since it is larger than the sum of its proper divisors (1).
130102122120823 is an equidigital number, since it uses as much as digits as its factorization.
130102122120823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 130102122120823 its reverse (328021221201031), we get a palindrome (458123343321854).
The spelling of 130102122120823 in words is "one hundred thirty trillion, one hundred two billion, one hundred twenty-two million, one hundred twenty thousand, eight hundred twenty-three".
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