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130102122120293 is a prime number
BaseRepresentation
bin11101100101001111000010…
…110001100000010001100101
3122001122122022120210111210102
4131211033002301200101211
5114023043121230322133
61140412031221233445
736255365604333551
oct3545170261402145
9561578276714712
10130102122120293
11385000001aa754
12127127b5562885
135779767928cbb
14241ad94dc6861
1510093c4c697e8
hex7653c2c60465

130102122120293 has 2 divisors, whose sum is σ = 130102122120294. Its totient is φ = 130102122120292.

The previous prime is 130102122120281. The next prime is 130102122120331. The reversal of 130102122120293 is 392021221201031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123608100654724 + 6494021465569 = 11117918^2 + 2548337^2 .

It is an emirp because it is prime and its reverse (392021221201031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130102122120293 - 246 = 59733377942629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130102122120203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051061060146 + 65051061060147.

It is an arithmetic number, because the mean of its divisors is an integer number (65051061060147).

Almost surely, 2130102122120293 is an apocalyptic number.

It is an amenable number.

130102122120293 is a deficient number, since it is larger than the sum of its proper divisors (1).

130102122120293 is an equidigital number, since it uses as much as digits as its factorization.

130102122120293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 130102122120293 in words is "one hundred thirty trillion, one hundred two billion, one hundred twenty-two million, one hundred twenty thousand, two hundred ninety-three".