Base | Representation |
---|---|
bin | 11101100101001111000010… |
… | …110001100000010001000011 |
3 | 122001122122022120210111202011 |
4 | 131211033002301200101003 |
5 | 114023043121230322014 |
6 | 1140412031221233351 |
7 | 36255365604333502 |
oct | 3545170261402103 |
9 | 561578276714664 |
10 | 130102122120259 |
11 | 385000001aa723 |
12 | 127127b5562857 |
13 | 5779767928c93 |
14 | 241ad94dc6839 |
15 | 10093c4c697c4 |
hex | 7653c2c60443 |
130102122120259 has 2 divisors, whose sum is σ = 130102122120260. Its totient is φ = 130102122120258.
The previous prime is 130102122120253. The next prime is 130102122120281. The reversal of 130102122120259 is 952021221201031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130102122120259 - 23 = 130102122120251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130102122120259.
It is not a weakly prime, because it can be changed into another prime (130102122120251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051061060129 + 65051061060130.
It is an arithmetic number, because the mean of its divisors is an integer number (65051061060130).
Almost surely, 2130102122120259 is an apocalyptic number.
130102122120259 is a deficient number, since it is larger than the sum of its proper divisors (1).
130102122120259 is an equidigital number, since it uses as much as digits as its factorization.
130102122120259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 130102122120259 in words is "one hundred thirty trillion, one hundred two billion, one hundred twenty-two million, one hundred twenty thousand, two hundred fifty-nine".
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