Base | Representation |
---|---|
bin | 10010111011000010011… |
… | …111110011110000000100 |
3 | 11121022102011012221100220 |
4 | 102323002133303300010 |
5 | 132301100332213412 |
6 | 2433211444304340 |
7 | 162642501120213 |
oct | 22730237636004 |
9 | 4538364187326 |
10 | 1300343241732 |
11 | 461521950847 |
12 | 1900223a20b0 |
13 | 95811255462 |
14 | 46d18db707a |
15 | 23c5912668c |
hex | 12ec27f3c04 |
1300343241732 has 48 divisors (see below), whose sum is σ = 3174680205312. Its totient is φ = 413472454560.
The previous prime is 1300343241727. The next prime is 1300343241749. The reversal of 1300343241732 is 2371423430031.
It is a junction number, because it is equal to n+sod(n) for n = 1300343241693 and 1300343241702.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6317494 + ... + 6520077.
It is an arithmetic number, because the mean of its divisors is an integer number (66139170944).
Almost surely, 21300343241732 is an apocalyptic number.
1300343241732 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1300343241732 is an abundant number, since it is smaller than the sum of its proper divisors (1874336963580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300343241732 is a wasteful number, since it uses less digits than its factorization.
1300343241732 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12837968 (or 12837966 counting only the distinct ones).
The product of its (nonzero) digits is 36288, while the sum is 33.
Adding to 1300343241732 its reverse (2371423430031), we get a palindrome (3671766671763).
The spelling of 1300343241732 in words is "one trillion, three hundred billion, three hundred forty-three million, two hundred forty-one thousand, seven hundred thirty-two".
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