Base | Representation |
---|---|
bin | 10010111011000000000… |
… | …010101001110011110111 |
3 | 11121022022021200220021001 |
4 | 102323000002221303313 |
5 | 132301004310410112 |
6 | 2433203413304131 |
7 | 162641461004332 |
oct | 22730002516367 |
9 | 4538267626231 |
10 | 1300302044407 |
11 | 461500672673 |
12 | 190010635047 |
13 | 9580585c942 |
14 | 46d13731619 |
15 | 23c556d9c57 |
hex | 12ec00a9cf7 |
1300302044407 has 2 divisors, whose sum is σ = 1300302044408. Its totient is φ = 1300302044406.
The previous prime is 1300302044309. The next prime is 1300302044417. The reversal of 1300302044407 is 7044402030031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1300302044407 - 239 = 750546230519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300302044417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650151022203 + 650151022204.
It is an arithmetic number, because the mean of its divisors is an integer number (650151022204).
Almost surely, 21300302044407 is an apocalyptic number.
1300302044407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300302044407 is an equidigital number, since it uses as much as digits as its factorization.
1300302044407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 28.
Adding to 1300302044407 its reverse (7044402030031), we get a palindrome (8344704074438).
The spelling of 1300302044407 in words is "one trillion, three hundred billion, three hundred two million, forty-four thousand, four hundred seven".
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