Base | Representation |
---|---|
bin | 10010111011000000000… |
… | …010101001100010101111 |
3 | 11121022022021200211202110 |
4 | 102323000002221202233 |
5 | 132301004310341221 |
6 | 2433203413255103 |
7 | 162641461001205 |
oct | 22730002514257 |
9 | 4538267624673 |
10 | 1300302043311 |
11 | 461500671867 |
12 | 190010634493 |
13 | 9580585c2ab |
14 | 46d13731075 |
15 | 23c556d9776 |
hex | 12ec00a98af |
1300302043311 has 16 divisors (see below), whose sum is σ = 1735862059008. Its totient is φ = 865805224800.
The previous prime is 1300302043289. The next prime is 1300302043319. The reversal of 1300302043311 is 1133402030031.
It is not a de Polignac number, because 1300302043311 - 26 = 1300302043247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300302043319) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38463826 + ... + 38497616.
It is an arithmetic number, because the mean of its divisors is an integer number (108491378688).
Almost surely, 21300302043311 is an apocalyptic number.
1300302043311 is a deficient number, since it is larger than the sum of its proper divisors (435560015697).
1300302043311 is a wasteful number, since it uses less digits than its factorization.
1300302043311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49142.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1300302043311 its reverse (1133402030031), we get a palindrome (2433704073342).
The spelling of 1300302043311 in words is "one trillion, three hundred billion, three hundred two million, forty-three thousand, three hundred eleven".
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