Base | Representation |
---|---|
bin | 11101100011111011011001… |
… | …000110001100100010010000 |
3 | 122001100001110220000101220200 |
4 | 131203323121012030202100 |
5 | 114020110143344030000 |
6 | 1140302454355335200 |
7 | 36246036023610666 |
oct | 3543733106144220 |
9 | 561301426011820 |
10 | 130012302330000 |
11 | 384759a9284902 |
12 | 126b9308bb1500 |
13 | 57711522521ac |
14 | 24168b3dd8c36 |
15 | 1006db9638500 |
hex | 763ed918c890 |
130012302330000 has 300 divisors, whose sum is σ = 481417206515388. Its totient is φ = 32630538240000.
The previous prime is 130012302329977. The next prime is 130012302330023. The reversal of 130012302330000 is 33203210031.
130012302330000 is a `hidden beast` number, since 1 + 30 + 0 + 1 + 2 + 302 + 330 + 0 + 0 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (130012302329977) and next prime (130012302330023).
It can be written as a sum of positive squares in 10 ways, for example, as 88935688247184 + 41076614082816 = 9430572^2 + 6409104^2 .
It is a tau number, because it is divible by the number of its divisors (300).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 40957681 + ... + 44017680.
Almost surely, 2130012302330000 is an apocalyptic number.
130012302330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130012302330000 is an abundant number, since it is smaller than the sum of its proper divisors (351404904185388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130012302330000 is a wasteful number, since it uses less digits than its factorization.
130012302330000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84975412 (or 84975388 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 130012302330000 its reverse (33203210031), we get a palindrome (130045505540031).
The spelling of 130012302330000 in words is "one hundred thirty trillion, twelve billion, three hundred two million, three hundred thirty thousand".
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