Base | Representation |
---|---|
bin | 11000001101110110… |
… | …10011101011101100 |
3 | 1020120001212221020210 |
4 | 30012323103223230 |
5 | 203111241043200 |
6 | 5550030542420 |
7 | 640115426331 |
oct | 140673235354 |
9 | 36501787223 |
10 | 13001112300 |
11 | 5571875110 |
12 | 262a067a10 |
13 | 12c26a1077 |
14 | 8b4978988 |
15 | 5115c1650 |
hex | 306ed3aec |
13001112300 has 288 divisors, whose sum is σ = 42308792064. Its totient is φ = 3055104000.
The previous prime is 13001112233. The next prime is 13001112323. The reversal of 13001112300 is 321110031.
It is a super-2 number, since 2×130011123002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 41536944 + ... + 41537256.
It is an arithmetic number, because the mean of its divisors is an integer number (146905528).
Almost surely, 213001112300 is an apocalyptic number.
13001112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13001112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21154396032).
13001112300 is an abundant number, since it is smaller than the sum of its proper divisors (29307679764).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001112300 is a wasteful number, since it uses less digits than its factorization.
13001112300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 689 (or 682 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 13001112300 its reverse (321110031), we get a palindrome (13322222331).
It can be divided in two parts, 130011 and 12300, that added together give a triangular number (142311 = T533).
The spelling of 13001112300 in words is "thirteen billion, one million, one hundred twelve thousand, three hundred".
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