Base | Representation |
---|---|
bin | 10111000110101100… |
… | …00000110100001101 |
3 | 1012000110120020210021 |
4 | 23203112000310031 |
5 | 200400424230013 |
6 | 5410503342141 |
7 | 616246251310 |
oct | 134326006415 |
9 | 35013506707 |
10 | 12404133133 |
11 | 529589a8a7 |
12 | 24a2151951 |
13 | 1228ac2462 |
14 | 85957a977 |
15 | 4c8e9da8d |
hex | 2e3580d0d |
12404133133 has 4 divisors (see below), whose sum is σ = 14176152160. Its totient is φ = 10632114108.
The previous prime is 12404133101. The next prime is 12404133143. The reversal of 12404133133 is 33133140421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12404133133 - 25 = 12404133101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12404133098 and 12404133107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12404133143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 886009503 + ... + 886009516.
It is an arithmetic number, because the mean of its divisors is an integer number (3544038040).
Almost surely, 212404133133 is an apocalyptic number.
It is an amenable number.
12404133133 is a deficient number, since it is larger than the sum of its proper divisors (1772019027).
12404133133 is an equidigital number, since it uses as much as digits as its factorization.
12404133133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1772019026.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12404133133 its reverse (33133140421), we get a palindrome (45537273554).
The spelling of 12404133133 in words is "twelve billion, four hundred four million, one hundred thirty-three thousand, one hundred thirty-three".
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