Base | Representation |
---|---|
bin | 10001110011001111011… |
… | …010000111111011011001 |
3 | 11022221102102112001010202 |
4 | 101303033122013323121 |
5 | 130020204103201433 |
6 | 2333541542151545 |
7 | 154243200134024 |
oct | 21631732077331 |
9 | 4287372461122 |
10 | 1223250443993 |
11 | 431860a92866 |
12 | 1790a81225b5 |
13 | 8b476513686 |
14 | 432c43aa1bb |
15 | 21c45ebaee8 |
hex | 11ccf687ed9 |
1223250443993 has 2 divisors, whose sum is σ = 1223250443994. Its totient is φ = 1223250443992.
The previous prime is 1223250443957. The next prime is 1223250444029. The reversal of 1223250443993 is 3993440523221.
It is a balanced prime because it is at equal distance from previous prime (1223250443957) and next prime (1223250444029).
It can be written as a sum of positive squares in only one way, i.e., 1221263691664 + 1986752329 = 1105108^2 + 44573^2 .
It is a cyclic number.
It is not a de Polignac number, because 1223250443993 - 26 = 1223250443929 is a prime.
It is not a weakly prime, because it can be changed into another prime (1223250443923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611625221996 + 611625221997.
It is an arithmetic number, because the mean of its divisors is an integer number (611625221997).
Almost surely, 21223250443993 is an apocalyptic number.
It is an amenable number.
1223250443993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223250443993 is an equidigital number, since it uses as much as digits as its factorization.
1223250443993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 47.
The spelling of 1223250443993 in words is "one trillion, two hundred twenty-three billion, two hundred fifty million, four hundred forty-three thousand, nine hundred ninety-three".
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