Base | Representation |
---|---|
bin | 11011110011110001100000… |
… | …011001101000010000110011 |
3 | 121001001020212010111020102010 |
4 | 123303301200121220100303 |
5 | 112012321324122132042 |
6 | 1112042105015254003 |
7 | 34522152354302154 |
oct | 3363614031502063 |
9 | 531036763436363 |
10 | 122305106052147 |
11 | 35a743389738a7 |
12 | 1187367067a303 |
13 | 5332425600975 |
14 | 222b854c4b92b |
15 | e216831e659c |
hex | 6f3c60668433 |
122305106052147 has 4 divisors (see below), whose sum is σ = 163073474736200. Its totient is φ = 81536737368096.
The previous prime is 122305106052119. The next prime is 122305106052149. The reversal of 122305106052147 is 741250601503221.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 122305106052147 - 26 = 122305106052083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122305106052149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20384184342022 + ... + 20384184342027.
It is an arithmetic number, because the mean of its divisors is an integer number (40768368684050).
Almost surely, 2122305106052147 is an apocalyptic number.
122305106052147 is a deficient number, since it is larger than the sum of its proper divisors (40768368684053).
122305106052147 is an equidigital number, since it uses as much as digits as its factorization.
122305106052147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40768368684052.
The product of its (nonzero) digits is 100800, while the sum is 39.
Adding to 122305106052147 its reverse (741250601503221), we get a palindrome (863555707555368).
The spelling of 122305106052147 in words is "one hundred twenty-two trillion, three hundred five billion, one hundred six million, fifty-two thousand, one hundred forty-seven".
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