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12224113 = 111111283
BaseRepresentation
bin101110101000…
…011001110001
3212000001022221
4232220121301
511112132423
61114001041
7205621546
oct56503161
925001287
1012224113
11699a180
124116181
1326c0005
1418a2bcd
151116e5d
hexba8671

12224113 has 4 divisors (see below), whose sum is σ = 13335408. Its totient is φ = 11112820.

The previous prime is 12224101. The next prime is 12224117. The reversal of 12224113 is 31142221.

12224113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12224113 - 25 = 12224081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12224117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555631 + ... + 555652.

It is an arithmetic number, because the mean of its divisors is an integer number (3333852).

Almost surely, 212224113 is an apocalyptic number.

It is an amenable number.

12224113 is a deficient number, since it is larger than the sum of its proper divisors (1111295).

12224113 is a wasteful number, since it uses less digits than its factorization.

12224113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1111294.

The product of its digits is 96, while the sum is 16.

The square root of 12224113 is about 3496.2999013243. The cubic root of 12224113 is about 230.3593186376.

Adding to 12224113 its reverse (31142221), we get a palindrome (43366334).

It can be divided in two parts, 1222 and 4113, that added together give a palindrome (5335).

The spelling of 12224113 in words is "twelve million, two hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 11 1111283 12224113