12144114041 has 4 divisors (see below), whose sum is σ = 12290428752. Its totient is φ = 11997799332.

The previous prime is 12144114001. The next prime is 12144114049. The reversal of 12144114041 is 14041144121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14041144121 = 23 ⋅610484527.

It is a cyclic number.

It is not a de Polignac number, because 12144114041 - 2¹⁸ = 12143851897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12144113998 and 12144114016.

It is not an unprimeable number, because it can be changed into a prime (12144114049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73157231 + ... + 73157396.

It is an arithmetic number, because the mean of its divisors is an integer number (3072607188).

Almost surely, 2^12144114041 is an apocalyptic number.

It is an amenable number.

12144114041 is a deficient number, since it is larger than the sum of its proper divisors (146314711).

12144114041 is an equidigital number, since it uses as much as digits as its factorization.

12144114041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146314710.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 12144114041 its reverse (14041144121), we get a palindrome (26185258162).

The spelling of 12144114041 in words is "twelve billion, one hundred forty-four million, one hundred fourteen thousand, forty-one".