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1214231440033 is a prime number
BaseRepresentation
bin10001101010110101110…
…101010110101010100001
311022002010212200011121001
4101222311311112222201
5124343221222040113
62325451001432001
7153503533642603
oct21526565265241
94262125604531
101214231440033
11428a52aa1687
121773ab79b601
138a669b3b441
1442aaa649173
15218b92d87dd
hex11ab5d56aa1

1214231440033 has 2 divisors, whose sum is σ = 1214231440034. Its totient is φ = 1214231440032.

The previous prime is 1214231440021. The next prime is 1214231440049. The reversal of 1214231440033 is 3300441324121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 975172050064 + 239059389969 = 987508^2 + 488937^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214231440033 - 213 = 1214231431841 is a prime.

It is a super-2 number, since 2×12142314400332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1214231439983 and 1214231440010.

It is not a weakly prime, because it can be changed into another prime (1214231440003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607115720016 + 607115720017.

It is an arithmetic number, because the mean of its divisors is an integer number (607115720017).

Almost surely, 21214231440033 is an apocalyptic number.

It is an amenable number.

1214231440033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214231440033 is an equidigital number, since it uses as much as digits as its factorization.

1214231440033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1214231440033 its reverse (3300441324121), we get a palindrome (4514672764154).

The spelling of 1214231440033 in words is "one trillion, two hundred fourteen billion, two hundred thirty-one million, four hundred forty thousand, thirty-three".