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12142034134000 = 2453174127132141
BaseRepresentation
bin1011000010110000100110…
…1000011010001111110000
31120222202201020100200210221
42300230021220122033300
53042413341214242000
641453550134302424
72362142632150441
oct260541150321760
946882636320727
1012142034134000
1139614537a9a21
12144125a7b7a14
136a0cb181a764
142dd96b42d2c8
15160c974e861a
hexb0b09a1a3f0

12142034134000 has 320 divisors, whose sum is σ = 31963173225984. Its totient is φ = 4443033600000.

The previous prime is 12142034133997. The next prime is 12142034134001. The reversal of 12142034134000 is 43143024121.

It is a super-2 number, since 2×121420341340002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12142034134001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 377757930 + ... + 377790070.

Almost surely, 212142034134000 is an apocalyptic number.

12142034134000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12142034134000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15981586612992).

12142034134000 is an abundant number, since it is smaller than the sum of its proper divisors (19821139091984).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12142034134000 is a wasteful number, since it uses less digits than its factorization.

12142034134000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32493 (or 32477 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12142034134000 its reverse (43143024121), we get a palindrome (12185177158121).

The spelling of 12142034134000 in words is "twelve trillion, one hundred forty-two billion, thirty-four million, one hundred thirty-four thousand".