Base | Representation |
---|---|
bin | 1011000010101010010101… |
… | …0101101110011010001011 |
3 | 1120222121100222012202102222 |
4 | 2300222211111232122023 |
5 | 3042401414441424001 |
6 | 41453111150044255 |
7 | 2362053141133502 |
oct | 260524525563213 |
9 | 46877328182388 |
10 | 12140351514251 |
11 | 396076aa27894 |
12 | 1440a6b1a968b |
13 | 6a0aa404807c |
14 | 2dd84bb8d839 |
15 | 160be992961b |
hex | b0aa556e68b |
12140351514251 has 2 divisors, whose sum is σ = 12140351514252. Its totient is φ = 12140351514250.
The previous prime is 12140351514229. The next prime is 12140351514259. The reversal of 12140351514251 is 15241515304121.
It is a happy number.
12140351514251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12140351514251 - 238 = 11865473607307 is a prime.
It is not a weakly prime, because it can be changed into another prime (12140351514259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070175757125 + 6070175757126.
It is an arithmetic number, because the mean of its divisors is an integer number (6070175757126).
Almost surely, 212140351514251 is an apocalyptic number.
12140351514251 is a deficient number, since it is larger than the sum of its proper divisors (1).
12140351514251 is an equidigital number, since it uses as much as digits as its factorization.
12140351514251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 35.
Adding to 12140351514251 its reverse (15241515304121), we get a palindrome (27381866818372).
The spelling of 12140351514251 in words is "twelve trillion, one hundred forty billion, three hundred fifty-one million, five hundred fourteen thousand, two hundred fifty-one".
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